EduNinja
IB Biology HL/Notes/D3.2 Inheritance

IB Biology HLD3.2 InheritanceNotes

Haploid gametes + fusion = diploid zygote

Inheritance begins with a chromosome-number rule. Meiosis makes haploid gametes, so each gamete carries one allele for each autosomal gene. Fertilization fuses two haploid gametes to form a diploid zygote, restoring two alleles, usually one from each parent.

Haploid gametes fuse during fertilization to form a diploid zygote.
Diploid organisms usually carry two alleles for each autosomal gene.
One allele usually comes from each parent.

Order the inheritance route.

Order
1
fertilization fuses gametes
2
meiosis forms haploid gametes
3
diploid zygote has two alleles
4
each gamete carries one autosomal allele

Genetic crosses in flowering plants

A genetic cross is a controlled fertilization experiment. In flowering plants, pollen transfer can be controlled so the parental generation is known. The F1 and F2 generations are then counted, and Punnett grids convert possible gametes into expected inheritance ratios.

Genetic crosses track parental, F1, and F2 generations using Punnett grids.
Flowering plant crosses control pollen transfer to study inheritance ratios.
Punnett grids predict expected ratios, not guaranteed outcomes in tiny samples.

Controlled pollen transfer lets geneticists connect generations to inheritance ratios.

Match each cross term to its role.

Match
Reasons
0/4

Match each cross term to its role.

Choose
P generation
F1
F2
Punnett grid

Genotype

Genotype is the allele combination an organism inherits for one gene or several genes. Homozygous means the two alleles match, such as AA or aa. Heterozygous means the alleles differ, such as Aa. Keep gene, allele, and genotype separate in wording.

Genotype is the allele combination inherited for a gene or genes.
Homozygous genotypes have matching alleles; heterozygous genotypes have different alleles.
AA and aa are homozygous; Aa is heterozygous.

Sort the genotypes.

Sort
Unsorted
3
Homozygous
0
Heterozygous
0

Phenotype

Phenotype is the observable characteristic or trait. It can be caused by genotype, environment, or an interaction between both. That is why the same genotype can sometimes show different phenotypes in different environments, and why a visible trait is not always enough to know the genotype.

Phenotype is the observable characteristic or trait.
Phenotype can be determined by genotype, environment, and their interaction.
A visible trait is not always a complete genotype diagnosis.

Sort each example by what mainly explains the phenotype.

Sort
Unsorted
3
Mostly genetic
0
Mostly environmental
0
Genotype + environment
0

Dominant and recessive alleles

Dominance is about expression in a heterozygote. A dominant allele is expressed when paired with a different recessive allele, so AA and Aa may share the dominant phenotype. A recessive phenotype appears only when no dominant allele masks it, usually aa. Dominant does not mean common or better.

Dominant alleles are expressed in heterozygotes.
Recessive alleles are expressed when no dominant allele masks them.
Dominant does not mean more common or stronger in a population.

Spot the error: a dominant allele must be the most common allele in the population.

Spot Errors

Phenotypic plasticity

Phenotypic plasticity means one genotype can produce different phenotypes in different environments. The DNA sequence does not change. Instead, environmental conditions alter gene expression or development, and the response can be adaptive or reversible.

Phenotypic plasticity is environment-driven phenotype change without genotype change.
It depends on altered gene expression and can be adaptive.
Do not confuse plasticity with mutation.

Spot the error: plasticity means the environment mutates the DNA sequence.

Spot Errors

Phenylketonuria (PKU)

PKU is a strong genotype-environment example. The disorder is autosomal recessive and affects phenylalanine metabolism. Newborn screening matters because a low-phenylalanine diet can reduce harmful effects even when the recessive genotype is present.

PKU is an autosomal recessive disorder affecting phenylalanine metabolism.
Low-phenylalanine diet and newborn screening reduce harmful effects.
PKU shows how environment can modify a genetic phenotype.

Which explanation best links PKU genotype to treatment?

Choose

SNPs and multiple alleles

A single nucleotide polymorphism, or SNP, is a single-base difference that can create a different allele. Populations can contain many alleles of the same gene, but a diploid individual still carries at most two alleles at that autosomal locus.

SNPs are single-base differences that can create different alleles.
Populations can have multiple alleles, but diploid individuals carry at most two.
Multiple alleles is a population idea, not extra alleles inside one diploid person.

Spot the error: because a gene has multiple alleles, each diploid individual carries all of them.

Spot Errors

ABO blood groups

ABO blood group is controlled by three alleles in the population: IA, IB, and i. IA and IB are codominant, so IAIB produces AB blood with both antigens. The i allele is recessive, so type O appears only as ii. Type A and type B can each be homozygous or heterozygous.

ABO blood group is controlled by IA, IB, and i alleles.
IA and IB are codominant; i is recessive, producing four blood phenotypes.
Type A can be IAIA or IAi; type B can be IBIB or IBi.

ABO inheritance combines multiple alleles with codominance.

Match each genotype to the ABO phenotype.

Match
Reasons
0/4

Match each genotype to the ABO phenotype.

Choose
IAIA or IAi
IBIB or IBi
IAIB
ii

Incomplete dominance and codominance

Incomplete dominance and codominance both break the simple dominant/recessive pattern. In incomplete dominance, the heterozygote has an intermediate phenotype. In codominance, both heterozygous alleles are expressed clearly, such as IA and IB in AB blood type.

Codominance expresses both heterozygous alleles, as in AB blood type.
Incomplete dominance gives an intermediate heterozygote phenotype.
The key distinction is both expressed versus intermediate blended phenotype.

Sort the heterozygote pattern.

Sort
Unsorted
4
Codominance
0
Incomplete dominance
0

Sex determination

Human chromosomal sex is usually determined by the XX or XY chromosome combination. An embryo with a Y chromosome usually has the SRY/TDF region, which directs testis development. Without that signal, development usually follows the ovarian pathway.

Human chromosomal sex is usually determined by XX or XY chromosome combination.
The SRY/TDF region on the Y chromosome directs testis development.
The Y chromosome carries the usual testis-determining signal.

Order the sex-determination mechanism.

Order
1
Y chromosome may carry SRY/TDF
2
zygote has XX or XY chromosomes
3
SRY/TDF directs testis development
4
testis pathway affects sexual development

Haemophilia

Haemophilia is an X-linked recessive blood-clotting disorder. Because males usually have only one X chromosome, a recessive allele on that X can be expressed in males. Females with one affected allele and one normal allele are carriers and are represented with X-linked allele notation.

Haemophilia is an X-linked recessive blood-clotting disorder.
Carrier females and affected males are represented with X-linked allele notation.
A male expresses the allele on his single X chromosome.

X-linked recessive alleles are written on X chromosomes, not as plain autosomal letters.

Match the notation to the interpretation.

Match
Reasons
0/4

Match the notation to the interpretation.

Choose
XH Xh
Xh Y
XH Y
Xh Xh

Pedigree charts

Pedigree charts show how a trait appears across generations. The pattern can help infer whether inheritance is autosomal dominant, autosomal recessive, or sex-linked. Strong answers use evidence from the chart, such as affected children from unaffected parents or sex bias among affected individuals.

Pedigree charts show family inheritance across generations.
Patterns help infer autosomal dominant, autosomal recessive, or sex-linked inheritance.
State the chart evidence, not only the inheritance label.

Pedigree patterns let you infer inheritance mode before assigning genotypes.

A pedigree shows two unaffected parents with an affected child. Which inference is most likely?

Decision
A pedigree shows two unaffected parents with an affected child. Which inference is most likely?

A pedigree shows two unaffected parents with an affected child. Which inference is most likely?

Choose

Continuous variation

Continuous variation produces many intermediate phenotypes rather than clear categories. It often results from polygenic inheritance plus environmental influence. Traits such as human skin colour, height, and body mass vary continuously because many genes and environmental factors contribute.

Continuous variation often results from polygenic inheritance plus environment.
Human skin colour, height, and body mass show many intermediate phenotypes.
Continuous traits are usually measured, not sorted into simple categories.

Sort the trait type.

Sort
Unsorted
4
Continuous variation
0
Discrete category
0

Box-and-whisker plots

Box-and-whisker plots summarize non-normal continuous data. The median shows the middle value, quartiles split the data, and the interquartile range shows the spread of the middle 50 percent. Whiskers and outliers help compare variation between groups without assuming a normal distribution.

Box-and-whisker plots summarize non-normal continuous data.
They show median, quartiles, interquartile range, maximum/minimum, and outliers.
Compare medians for central tendency and IQR/whiskers for spread.

A box plot shows spread, median and outliers in continuous data.

Label the parts of a box-and-whisker plot.

Label
Labels
6

Label the parts of a box-and-whisker plot.

Choose

Segregation and independent assortment

HL inheritance starts in meiosis. Alleles segregate because homologous chromosomes separate, so each gamete receives one allele from each pair. Unlinked genes assort independently because bivalents orient randomly at metaphase I, creating different chromosome combinations in gametes.

Alleles segregate as homologous chromosomes separate during meiosis.
Unlinked genes assort independently through random bivalent orientation.
Independent assortment applies to unlinked genes, not tightly linked loci.

Random bivalent orientation explains independent assortment of unlinked genes.

Match the meiosis event to the inheritance rule.

Match
Reasons
0/4

Match the meiosis event to the inheritance rule.

Choose
homologous chromosomes separate
random bivalent orientation
linked loci close together
gamete formation

Dihybrid crosses

A dihybrid cross follows two genes at the same time. For unlinked autosomal genes, Aa Bb parents can make AB, Ab, aB, and ab gametes. Aa Bb x Aa Bb gives the classic 9:3:3:1 F2 phenotype ratio, while Aa Bb x aabb gives a 1:1:1:1 test-cross ratio.

Dihybrid crosses track inheritance of two genes simultaneously.
Unlinked autosomal genes can produce 9:3:3:1 F2 or 1:1:1:1 test-cross ratios.
Write genotypes by gene pairs, for example Aa Bb, not ABab.

Dihybrid ratios come from gamete combinations plus a Punnett grid.

Which ratio fits Aa Bb x Aa Bb for two unlinked genes with complete dominance?

Choose

Which ratio fits Aa Bb x Aa Bb for two unlinked genes with complete dominance?

Choose

Human gene loci

Genome databases identify a gene’s chromosome location, locus, and polypeptide product. This matters for inheritance because genes on different chromosomes are unlinked, while close loci on one chromosome can be linked. Genes far apart on one chromosome can behave as unlinked if recombination is frequent.

Genome databases identify human gene loci and polypeptide products.
Genes on different chromosomes are unlinked; close loci on one chromosome can be linked.
Genes far apart on one chromosome can behave as unlinked if recombination is frequent.

Match the database field to its use.

Match
Reasons
0/4

Autosomal gene linkage

Autosomal linkage means two genes are on the same non-sex chromosome. Linked alleles tend to be inherited together because they travel on the same chromosome. Crossing over between the loci can separate them, but closer loci recombine less often, so parental combinations are more common.

Linked autosomal genes are on the same non-sex chromosome.
Linked genes tend to be inherited together unless crossing over occurs between loci.
In linkage notation, alleles are shown beside vertical homologous chromosome lines.

Linked genes sit on the same autosome and tend to be inherited together.

Spot the error: linked genes assort independently because they are on the same chromosome.

Spot Errors

Spot the error: linked genes assort independently because they are on the same chromosome.

Choose

Recombinants

A recombinant has an allele combination different from the parental chromosomes. In linked-gene test crosses, parental phenotypes are usually the most frequent classes. Recombinant phenotypes are less frequent because they require crossing over between the linked loci.

Recombinants have allele combinations different from parental chromosomes.
Crossing over between linked genes produces fewer recombinants than parental types.
Identify recombinants by comparing offspring classes with parental combinations.

Sort the offspring class.

Sort
Unsorted
4
Parental type
0
Recombinant type
0

Chi-squared test

A chi-squared test asks whether observed genetic data fit an expected ratio closely enough. Calculate from observed and expected values, use degrees of freedom, and compare with the p = 0.05 critical value. If chi-squared is greater than the critical value, reject the null hypothesis.

Chi-squared tests whether observed genetic data fit expected ratios.
Use observed/expected values, degrees of freedom, and p = 0.05 significance.
If chi-squared exceeds the critical value, reject the null hypothesis.

Chi-squared tests whether observed offspring data fit an expected inheritance ratio.

Order the chi-squared decision workflow.

Order
1
find degrees of freedom
2
calculate expected counts
3
state expected genetic ratio
4
compare with p = 0.05 critical value
5
accept or reject the null hypothesis
6
calculate chi-squared from observed and expected

Order the chi-squared decision workflow.

Choose
state expected genetic ratio
calculate expected counts
calculate chi-squared from observed and expected
find degrees of freedom
compare with p = 0.05 critical value
accept or reject the null hypothesis

Retrieve the Core Inheritance Route

Review

Core D3.2 is secure when the student can move from allele rules into predictions and evidence: gametes form genotypes, genotypes can produce phenotypes, different dominance patterns need different notation, and pedigrees or plots require evidence-based interpretation.

haploid gametes carry one allele and fertilization restores a diploid genotype
dominance, codominance, incomplete dominance, environment, and plasticity affect the observed trait
PKU, ABO, sex determination, and haemophilia use different inheritance rules and notation
pedigrees infer inheritance patterns and box plots summarize continuous variation

Match each retrieval cue to its exam-use meaning.

Match
Reasons
0/4

Retrieve the HL Inheritance Route

Review

HL D3.2 is secure when chromosome behaviour explains the ratios: segregation and independent assortment produce unlinked dihybrid expectations, gene loci explain linkage, recombinants reveal crossing over, and chi-squared decides whether observed counts fit the expected model.

homologous chromosomes separate and random bivalent orientation assort unlinked genes
unlinked autosomal genes can produce 9:3:3:1 or 1:1:1:1 ratios
linked genes give more parental types and fewer recombinants after crossing over
observed counts are compared with expected ratios using df and p = 0.05

Match each retrieval cue to its exam-use meaning.

Match
Reasons
0/4

Transfer: Solve Core Inheritance Questions

Exam Practice

Core inheritance exam questions reward disciplined reasoning. First identify the inheritance rule, then write the correct notation or evidence, then state the phenotype, ratio, or conclusion. This prevents the common mistake of writing definitions without solving the genetic problem.

Use allele and genotype notation correctly for monohybrid, ABO, PKU, haemophilia, and sex-determination contexts.
Connect genotype, dominance pattern, environment, or plasticity to phenotype.
Use pedigree or box-plot evidence to justify an inheritance or variation conclusion.

Deduce or explain an inheritance outcome using genotype notation, phenotype evidence, or a family/data display.

Deduce or explain an inheritance outcome using genotype notation, phenotype evidence, or a family/data display.

Choose

Match each exam move to the mark it earns.

Match
Reasons
0/3

Transfer: Solve HL Linkage and Chi-Squared Questions

Exam Practice

HL inheritance transfer is about deciding whether the expected ratio should be Mendelian or linked, then testing the evidence. Start from meiosis and gene location, predict gametes or ratios, identify parental and recombinant classes, and use chi-squared when observed counts need a statistical conclusion.

Explain segregation and independent assortment from meiosis before using dihybrid ratios.
Use gene loci, linkage, crossing over, and recombinant frequency to interpret offspring classes.
Apply chi-squared with observed/expected values, degrees of freedom, p = 0.05, and a null-hypothesis conclusion.

Explain whether inheritance data fit independent assortment or linkage, and use chi-squared to support a conclusion where appropriate.

Explain whether inheritance data fit independent assortment or linkage, and use chi-squared to support a conclusion where appropriate.

Choose

Match each exam move to the mark it earns.

Match
Reasons
0/3